14x^2-25xq-25q^2=0

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Solution for 14x^2-25xq-25q^2=0 equation:


Simplifying
14x2 + -25xq + -25q2 = 0

Reorder the terms:
-25qx + -25q2 + 14x2 = 0

Solving
-25qx + -25q2 + 14x2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-5q + -7x)(5q + -2x) = 0

Subproblem 1

Set the factor '(-5q + -7x)' equal to zero and attempt to solve: Simplifying -5q + -7x = 0 Solving -5q + -7x = 0 Move all terms containing q to the left, all other terms to the right. Add '7x' to each side of the equation. -5q + -7x + 7x = 0 + 7x Combine like terms: -7x + 7x = 0 -5q + 0 = 0 + 7x -5q = 0 + 7x Remove the zero: -5q = 7x Divide each side by '-5'. q = -1.4x Simplifying q = -1.4x

Subproblem 2

Set the factor '(5q + -2x)' equal to zero and attempt to solve: Simplifying 5q + -2x = 0 Solving 5q + -2x = 0 Move all terms containing q to the left, all other terms to the right. Add '2x' to each side of the equation. 5q + -2x + 2x = 0 + 2x Combine like terms: -2x + 2x = 0 5q + 0 = 0 + 2x 5q = 0 + 2x Remove the zero: 5q = 2x Divide each side by '5'. q = 0.4x Simplifying q = 0.4x

Solution

q = {-1.4x, 0.4x}

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